[virtmach] instruction set
18 Apr 2000 23:28:08 +0100
Dennis Yelle <firstname.lastname@example.org> writes:
> Because this:
> if ( a < b )
> is not the same as this:
> if ( (a-b) < 0 )
In what mathematics? Even for unsigned integers (a, b) the result of
the subtraction operator *must* be a signed integer and the inequality
still holds. Now you can't promote the signed result of the
subtraction to an unsigned value without major lossage, but that's a
whole different problem.
As I've gained more experience with Perl it strikes me that it resembles
Lisp in many ways, albeit Lisp as channeled by an awk script on acid.
-- Tim Moore (on comp.lang.lisp)