[virtmach] instruction set

David Rush kumo@bellsouth.net
18 Apr 2000 23:28:08 +0100

Dennis Yelle <dennis51@jps.net> writes:
> Because this:
>    if ( a < b )
> is not the same as this:
>    if ( (a-b) < 0 )

In what mathematics? Even for unsigned integers (a, b) the result of
the subtraction operator *must* be a signed integer and the inequality
still holds. Now you can't promote the signed result of the
subtraction to an unsigned value without major lossage, but that's a
whole different problem.

david rush
As I've gained more experience with Perl it strikes me that it resembles
Lisp in many ways, albeit Lisp as channeled by an awk script on acid.
	-- Tim Moore (on comp.lang.lisp)