[virtmach] instruction set

[David Rush]

Dennis Yelle <dennis51@jps.net> writes:
> Because this:
>    if ( a < b )
> is not the same as this:
>    if ( (a-b) < 0 )

In what mathematics? Even for unsigned integers (a, b) the result of
the subtraction operator *must* be a signed integer and the inequality
still holds. Now you can't promote the signed result of the
subtraction to an unsigned value without major lossage, but that's a
whole different problem.

david rush
-- 
As I've gained more experience with Perl it strikes me that it resembles
Lisp in many ways, albeit Lisp as channeled by an awk script on acid.
	-- Tim Moore (on comp.lang.lisp)